1822 Rhode Island gubernatorial election

1822 Rhode Island gubernatorial election

← 1821 April 17, 1822[1] 1823 →
 
Nominee William C. Gibbs
Party Democratic-Republican
Popular vote 2,092
Percentage 100%


Governor before election

William C. Gibbs
Democratic-Republican

Elected Governor

William C. Gibbs
Democratic-Republican

The 1822 Rhode Island gubernatorial election was an uncontested election held on April 17, 1822 to elect the Governor of Rhode Island. William C. Gibbs, the Democratic-Republican nominee, was the only candidate and so won with 100% of the vote.

General election[edit]

Candidates[edit]

  • William C. Gibbs, Governor since 1821.[2]

Results[edit]

1822 Rhode Island gubernatorial election[3][4]
Party Candidate Votes % ±%
Democratic-Republican William C. Gibbs (incumbent) 2,092 100%
Majority 2,092 100%
Democratic-Republican hold Swing

County results[edit]

County results
County[3] William Gibbs

Democratic-Republican

Total votes
# %
Bristol 141 100% 141
Kent 349 100% 349
Newport 514 100% 514
Providence 755 100% 755
Washington 333 100% 333
Totals 2,092 100% 2,092

References[edit]

  1. ^ "Election". The Rhode-Island Republican. Newport, R.I. April 24, 1822. p. 2. Retrieved October 24, 2021.
  2. ^ "Governor William Channing Gibbs". National Governor's Association. Archived from the original on March 5, 2017.
  3. ^ a b "Rhode Island 1822 Governor". A New Nation Votes: American Election Returns 1787-1825. January 11, 2012. Retrieved June 2, 2022.
  4. ^ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. p. 232. ISBN 9780786414390.