1896 Rhode Island gubernatorial election

1896 Rhode Island gubernatorial election

← 1895 April 1, 1896 1897 →

Dem PRO Nominee Charles W. Lippitt George L. Littlefield Thomas H. Peabody Party Republican Democratic Prohibition Popular vote 28,472 17,061 2,950 Percentage 56.40% 33.79% 5.84%

Governor before election Charles W. Lippitt Republican Elected Governor Charles W. Lippitt Republican

Elections in Rhode Island
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Ballot measures 2020 Question 1
Providence Mayoral elections 1998 2002 2006 2010 2014 2018 2022
v t e

The 1896 Rhode Island gubernatorial election was held on April 1, 1896. Incumbent Republican Charles W. Lippitt defeated Democratic nominee George L. Littlefield with 56.40% of the vote.

General election[edit]

Candidates[edit]

Major party candidates

• Charles W. Lippitt, Republican
• George L. Littlefield, Democratic

Other candidates

• Thomas H. Peabody, Prohibition
• Edward W. Theinert, Socialist Labor
• Henry A. Burlingame, People's

Results[edit]

References[edit]