1806 United States House of Representatives election in Delaware|
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The 1806 United States House of Representatives election in Delaware was held on October 7, 1806, to elect the U.S. representative from Delaware's at-large congressional district. Incumbent Federalist James M. Broom faced re-election to a full term after winning the previous year's special election. He was challenged by three Democratic-Republicans.
Broom was re-elected with over 60% of the vote, with neither opponent coming close to unseating him.
Results[edit]
Results by county[edit]
County | Broom# | Broom% | Fitzgerald# | Fitzgerald% | Haslet# | Haslet% | Montgomery# | Montgomery% | Total |
Kent | 709 | 95.94% | | | | | 30 | 4.06% | 739 |
New Castle | 928 | 43.36% | 830 | 38.79% | 382 | 17.85% | | | 2,140 |
Sussex | 719 | 71.05% | | | | | 293 | 28.95% | 1,012 |
References[edit]
See also[edit]
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Elections spanning two years (through 1879) | |
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Elections held in a single year (starting 1880) | Regulars and even-year specials | |
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Odd-year specials | |
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Elections by state | |
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Seat ratings | |
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Speaker elections | |
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Summaries | |
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